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dimaraw [331]
3 years ago
10

Find the value of X.

Mathematics
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

<h2>x=√30</h2>

Given,

CB=X

CD=3

CA=3+7=10

HERE,

{(cb)}^{2}  = cd  \times ca \\  {x}^{2} = 3 \times 10 \\  {x}^{2}   = 30 \\ x =  \sqrt{30}

Hope this helps...

Good luck on your assignment..

fenix001 [56]3 years ago
3 0
X= square root of 30
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\large{\green}\fcolorbox{purple}{pink}{\bf{\underline{\red{\color{red}Answer}}}}

6x + 20

Step-by-step explanation:

  • <u>To</u><u> </u><u>find</u><u> </u><u>:</u><u>-</u>

Perimeter of rectangle

  • <u>Given</u><u> </u><u>:</u><u>-</u>

Length = 2x + 7

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  • <u>Solution</u><u> </u><u>:</u><u>-</u>

<em>We</em><em> </em><em>know</em><em> </em><em>that</em>

<em>\mathfrak {perimeter \: of \: rectangle =2(length + breadth) }</em>

<em>Now</em><em> </em><em>we</em><em> </em><em>will</em><em> </em><em>substitute</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>length</em><em> </em><em>and</em><em> </em><em>breadth</em>

<em>\sf  \longmapsto perimeter = 2 \{(2x + 7) + (x + 3) \} \\  \\  \\  \sf \longmapsto perimeter = 2 \{3x + 10 \} \\  \\  \\  \sf  \longmapsto perimeter = 6x + 20</em>

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2 years ago
Peter needs to build a fence around his small garden. The length of the fence can be no more than 10 ft., and he has 50 ft. of f
dsp73

Answer:

A backyard farmer wants to enclose a rectangular space for a new garden. She has purchased 80 feet of wire fencing to enclose 3 sides, and will put the 4th side against the backyard fence. Find a formula for the area enclosed by the fence if the sides of fencing perpendicular to the existing fence have length

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In a scenario like this involving geometry, it is often helpful to draw a picture. It might also be helpful to introduce a temporary variable,

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Since we know we only have 80 feet of fence available, we know that

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Now we are ready to write an equation for the area the fence encloses. We know the area of a rectangle is length multiplied by width, so

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This formula represents the area of the fence in terms of the variable length

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Step-by-step explanation:

it's in the answer

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\begin{gathered} |x+\frac{5}{3}|-3>6 \\  \\ Take-3\text{ }to\text{ }the\text{ }other\text{ }side\text{ }of\text{ }the\text{ }inequality\text{ }sign \\  \\ |x+\frac{5}{3}|>6+3 \\  \\ |x+\frac{5}{3}|>9 \end{gathered}

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