The correct answer is 558
Answer: (0, 2)
3x = y - 2
6x = 4 - 2y
3x = y - 2
- y - y
-y + 3x = - 2
- 3x - 3x
-y = - 3x - 2
/-1 /-1
y = 3x + 2
6x = 4 - 2y
+ 2y + 2y
2y + 6x = 4
- 6x - 6x
2y = - 6x + 4
/2 /2
y = -3x + 2
y = 3x + 2
y = -3x + 2
3x + 2 = -3x + 2
- 2 - 2
3x = -3x
/3 /3
x = 0
y = 3x + 2
y = 3(0) + 2
y = 2
(x, y) --> (0, 2)
Therefore, the two equations intersect at (0, 2)
Hope this helps!
Answer:
Step-by-step explanation:
Oi Dri
Statement A is the false one.
