Is √2 irrational or rational?

Arte-miy333 [17]

The answer might be B

7 0

2 years ago

Suppose you can somehow choose two people at random who took the SAT in 2014. A reminder that scores were Normally distributed w

Sindrei [870]

Answer:

22.29% probability that both of them scored above a 1520

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 1497, \sigma = 322$

The first step to solve the question is find the probability that a student has of scoring above 1520, which is 1 subtracted by the pvalue of Z when X = 1520.

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1520 - 1497}{322}$

$Z = 0.07$

$Z = 0.07$ has a pvalue of 0.5279

1 - 0.5279 = 0.4721

Each students has a 0.4721 probability of scoring above 1520.

What is the probability that both of them scored above a 1520?

Each students has a 0.4721 probability of scoring above 1520. So

$P = 0.4721*0.4721 = 0.2229$

22.29% probability that both of them scored above a 1520

8 0

2 years ago

A triangle has sides measuring 8 inches, 5 inches and 4 inches. How would you classify it?

Zina [86]

Answer:

I wouldn't classify it i would ignore it.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

Given:

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

Solve for $x$ in the 1st equation:

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

Substitute the value of $x$ into the 2nd equation and solve for $z$ :

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

Substitute the value of $z$ into the 3rd equation and solve for $y$ :

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

Plug $y=3$ into the solved expression for $z$ and evaluate to solve for $z$ :

$z=16-7(3)$

$z=16-21$

$z=-5$

Plug $z=-5$ into the solved expression for $x$ and evaluate to solve for $x$ :

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

6 0

3 years ago

WILL MARK BRAINIEST IF CORRECT.

bonufazy [111]

Answer:

1, 2, 5 and 6 are the answers.

Step-by-step explanation:

2 is correct because the arrow shows that the number line continues till infinity. 5 is correct because any fraction is possible as no restriction of integer value is placed. Any number less than 7 is not included. There are some confusions with 1 as it's not a solid color, So, I assume -7 is not included.

3 0

3 years ago