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MrMuchimi
3 years ago
9

Fully condense the expression. Assume that all variables represent positive numbers. (log x -2 log y+ 3 log z) (10 points)

Mathematics
1 answer:
AfilCa [17]3 years ago
5 0

Answer:  The required condensed expression is \log\dfrac{xz^3}{y^2}.

Step-by-step explanation:  We are given to fully condense the following logarithmic expression assuming that all variables represent positive numbers :

E=\log x-2\log y+3\log z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

We will be using the following properties of logarithms :

(i)~\log a^b=b\log a,\\\\(ii)~\log a+\log b=\log(ab),\\\\(iii)~\log a-\log b=\log\dfrac{a}{b}.

Therefore, from expression (i), we get

E\\\\=\log x-2\log y+3\log z\\\\=\log x-\log y^2+\log z^3\\\\=\log(xz^3)-\log y^2\\\\=\log\dfrac{xz^3}{y^2}.

Thus, the required condensed expression is \log\dfrac{xz^3}{y^2}.

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1.22=r^12

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F=100(1.22^(t/12))  now it will produce monthly populations...

Say we did the same as before but instead of 5 years you have 60 months...

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4 years ago
One kilometer is equal to 0.62 miles. Which best describes the relationship?
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The vertices of a rectangle are (1, -3), (4,0), (0,4) and (-3,1). What is the area of the rectangle? ​
motikmotik

Answer:

48

Step-by-step explanation:

You can use a graphing calculator like desmos or draw your own graph to figure this out. Start by graphing each of those points. Then count the width and height. Multiply them to get the area. The width and height of the rectangle were 6 and 8, so the area is 48

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Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.
Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

|AB|=\sqrt{(4--1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}

\Rightarrow |AB|=\sqrt{5^2+(0)^2}

\Rightarrow |AB|=\sqrt{25}

\Rightarrow |AB|=5 units.

The length of side BC

|BC|=\sqrt{(3-4)^2+(-1-2)^2}

\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}

\Rightarrow |BC|=\sqrt{1+9}

\Rightarrow |BC|=\sqrt{10}

The length of side AC

|AC|=\sqrt{(3--1)^2+(-1-2)^2}

We simplify to obtain;

|AC|=\sqrt{(3+1)^2+(-3)^2}

\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}

|AC|=\sqrt{16+9}

|AC|=\sqrt{25}

|AC|=5\:units

Since |AC|=5\:units=|AB|, the given triangle is an isosceles triangle.

The correct answer is

6 0
4 years ago
Read 2 more answers
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