Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
SQUARES BECAUSE THEY ARE IN THE MIDDLE DUMMY
Answer:D
Step-by-step explanation:y-4=3(x-1)
y-4=0 3(x-1)
y=-4 , 3x-3
y=-4=3x-3
3 3
y=-4, = x=1
y-x=1+4=5
Answer:
B)1.1
Step-by-step explanation:
I'm 100% sure
Answer:
62.34
Step-by-step explanation:
Substitute n = 0 to n = 5 into the expression and sum the terms, that is
3 [
+
+
+
+
+
]
= 3 [ 1 +
+
+
+
+
]
= 3(
)
= 3 × 20.781
= 62.34 ( to the nearest hundredth )