F(x)= x^2 -16x+63 find the x-intercepts of this function
2 answers:
Answer:
The x-intercepts will be, x= 7 or x =9
Step-by-step explanation:
f(x)= x^2 -16x+63
At the x-intercept, f(x) is zero.
Therefore;
x² - 16x + 63 = 0
solving it quadratically;
product = 63
Sum = -16
x² - 9x - 7x + 63 = 0
x(x-9) - 7( x-9) = 0
(x-7) (x-9) = 0
x = 7 or x = 9
Therefore;
The x-intercepts will be, x= 7 or x =9
Answer:
(7, 0) and (9, 0)
Step-by-step explanation:
The x-intercepts refers to the points where the graph of the function crosses the x-axis, or simply the zeroes of the function. In this case, we can determine these points analytically or graphically. We simply graph the function;
y = x^2 -16x +63 then determine where the function crosses the x-axis; see the attachment below;
The x-intercepts of this function are;
(7, 0) and (9, 0)
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