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Mademuasel [1]
3 years ago
15

F(x)= x^2 -16x+63 find the x-intercepts of this function

Mathematics
2 answers:
Ahat [919]3 years ago
8 0

Answer:

The x-intercepts will be, x= 7 or x =9

Step-by-step explanation:

f(x)= x^2 -16x+63

At the x-intercept, f(x) is zero.

Therefore;

x² - 16x + 63 = 0

solving it quadratically;

product = 63

Sum       = -16

x² - 9x - 7x + 63 = 0

x(x-9) - 7( x-9) = 0

(x-7) (x-9) = 0

x = 7 or x = 9

Therefore;

The x-intercepts will be, x= 7 or x =9

Grace [21]3 years ago
3 0

Answer:

(7, 0) and (9, 0)

Step-by-step explanation:

The x-intercepts refers to the points where the graph of the function crosses the x-axis, or simply the zeroes of the function. In this case, we can determine these points analytically or graphically. We simply graph the function;

y = x^2 -16x +63 then determine where the function crosses the x-axis; see the attachment below;

The x-intercepts of this function are;

(7, 0) and (9, 0)

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