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2 years ago

F(x)= x^2 -16x+63 find the x-intercepts of this function

Mathematics

2 answers:

Ahat [919]2 years ago

8 0

Answer:

The x-intercepts will be, x= 7 or x =9

Step-by-step explanation:

f(x)= x^2 -16x+63

At the x-intercept, f(x) is zero.

Therefore;

x² - 16x + 63 = 0

solving it quadratically;

product = 63

Sum = -16

x² - 9x - 7x + 63 = 0

x(x-9) - 7( x-9) = 0

(x-7) (x-9) = 0

x = 7 or x = 9

Therefore;

The x-intercepts will be, x= 7 or x =9

Grace [21]2 years ago

3 0

Answer:

(7, 0) and (9, 0)

Step-by-step explanation:

The x-intercepts refers to the points where the graph of the function crosses the x-axis, or simply the zeroes of the function. In this case, we can determine these points analytically or graphically. We simply graph the function;

y = x^2 -16x +63 then determine where the function crosses the x-axis; see the attachment below;

The x-intercepts of this function are;

(7, 0) and (9, 0)

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2 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

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Answer:

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This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

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$\ln{e^{-6r}} = \ln{0.97}$

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$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

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