Answer: The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8
What is an equation?
An equation is an expression that shows the relationship between two or more variables and numbers.
A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.
The height of the ball at time t is given as h = -16t² + 14t + 6 while the height of the receiver hand at time t is given as h = -16t² + 10t + 8
Answer:
Relative frequency is 7.41% or 0.0741
Step-by-step explanation:
Given
The Attached Table
Required
Calculate the relative frequency of the class with lower limit 27
Relative Frequency is calculated by dividing individual frequency by the total frequency
Mathematically,
The total frequency of the given data is 6+8+4+2+5+2
The class with lower limit 27 has a frequency of 2;
Hence;
becomes
(Approximated)
You may also leave your answer in percentage form
Hence, the relative frequency is 7.41% or 0.0741
A . Because one you make the ratio 80:48 you simplify (divide until you can divide anymore ).
The correct answer for the question that is being presented above is this one: "18.12."
The image of this triangle is an isosceles triangle<span> with the base being 33 m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from each other. so we need to find the length of the left leg AB.</span>
Answer:
(x+1)(2x+5)
Step-by-step explanation:
f(x) = 2x² + 7x + 5
Factor the expression by grouping. First, the expression needs to be rewritten as 2x²+ax+bx+5. To find a and b, set up a system to be solved.
a+b=7
ab=2×5=10
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 10.
1,10
2,5
Calculate the sum for each pair.
1+10=11
2+5=7
The solution is the pair that gives sum 7.
a=2
b=5
2x²+7x+5 as (2x²+2x)+(5x+5).
(2x²+2x)+(5x+5)
Factor out 2x in the first and 5 in the second group.
2x(x+1)+5(x+1)
Factor out common term x+1 by using distributive property.
(x+1)(2x+5)
