Find the 8th term of geometric sequence {a_{n}, n = 1, 2, 3, . . .} with common ratio r = 0.5 and first term a_{1} = 2.

1 answer:

6 0

$a_n=a_1\cdot q^{n-`1}\\\\a_1=2;\ q=0.5=\frac{1}{2}\\\\\\a_8=a_1\cdot q^{8-1}=a_1\cdot q^7\\\\a_8=2\cdot\left(\frac{1}{2}\right)^7=2\cdot\frac{1}{2^7}=2\cdot\frac{1}{128}=\frac{1}{64}\\\\\\Answer:a_8=\frac{1}{64}$

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If Ryan uses only 3/8 cup syrup out of the giant bottle each time he eats pancakes, how many times will he be able to eat pancak

elena55 [62]

Answer:

128 times

Step-by-step explanation:

Total cups = volume per meal × no. of meals

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What is the common ratio of 2, 10/3, 50/9

mojhsa [17]

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<u>Solution:</u>

Given, series of elements are $2, \frac{10}{3}, \frac{50}{9}$

We have to find the common ratio of the above given series.

We know that, common ratio of an G.P is division of any number in that series with the previous number of the series.

So, now take $\frac{10}{3}$ and 2

$\text { Then, common ratio }=\frac{\frac{10}{3}}{2}$

$\begin{array}{l}{\text { Common ratio }=\frac{10}{3} \times \frac{1}{2}} \\\\ {\text { Common ratio }=\frac{10}{3 \times 2}=\frac{10}{6}}\end{array}$