Sarah increase the amount of carbs she eats everyday from 225g to 325 grams. What percentage did Sarah increase the amount of ca
2 answers:
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The fraction can simplify down to 
convert it to a fraction and the yearly increase is 1.5%
2. Well on average there are 365 days in a year. Dividing 93 million by 365 will get your increase per day.
There are 24 hours in a day, so that figure is further divided by 24.
There are also 60 minutes in an hour therefore furthermore divided by 60.
= 176 therefore true
2. Well on average there are 365 days in a year. Dividing 93 million by 365 will get your increase per day.
There are 24 hours in a day, so that figure is further divided by 24.
There are also 60 minutes in an hour therefore furthermore divided by 60.
= 176 therefore true
Answer:
the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251
Option A) is the correct answer.
Step-by-step explanation:
Given the data in the question;
we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.
as in it in the question;
obtained mean is 9.8 which is obviously not equal to 8.3
But still we fail to reject the null hypothesis says mean is 8.3
Hence we have to find the probability of type 11 error
given that; it is right tailed and o.5, it corresponds to 1.645
so
z is equal to 1.645
z = (x-μ)/
where our standard deviation s = 3.8
sample size n = 50
mean μ = 8.3
we substitute
1.645 = (x - 8.3)/
1.645 = (x - 8.3) / 0.5374
0.884023 = x - 8.3
x = 0.884023 + 8.3
x = 9.18402
so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645
As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value
so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402
Now, for mean 9.8 and standard deviation 3.8 and sample size 50
Z = (9.18402 - 9.8)/
Z = -0.61598 / 0.5374
Z = - 1.1462 ≈ - 1.15
from the z-score table;
P(z<-1.15) = 0.1251
Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251
Option A) is the correct answer.