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NNADVOKAT [17]
3 years ago
6

How do I find the surface area of a cone

Mathematics
1 answer:
katen-ka-za [31]3 years ago
8 0
Find circumference and height of cone and multiply
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5. Which equation is true when the value of x is -2<br> Helppppp
DENIUS [597]

Answer:

B

Step-by-step explanation:

because 4(x+3)=6x+16 is true

4(-2+3)=6(-2)+16

4(1)= -12+16

4=4

so the equation is true

hope it helped

4 0
3 years ago
One angle of a triangle measures 65°. The other two angles are in a ratio of 3:20. What are the measures of those two angles?
Nataly_w [17]

Answer:

15° and 100°

Step-by-step explanation:

65 + 3x + 20x = 180

23x = 115

x = 5

3 × 5 = 15, 20 × 5 = 100. So the other two angles measure 15° and 100°.

3 0
2 years ago
The midpoint of is M(4,-3) One endpoint is G(-2,2). find the coordinates of end point​
motikmotik
The other endpoint is (10, -8
4 0
3 years ago
How do I solve this out??
GuDViN [60]
<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0
3 years ago
Let's consider the time as a discrete variable with an increment of 1 minute. You arrive at a bus stop at 10 AM, knowing that th
Dafna11 [192]

Answer:

a) 2/3

b) 1/3

Step-by-step explanation:

Let X be the random event that measures the time you will have to wait.  

Since time is uniformly distributed between 10 and 10:30 in intervals of 1 minute

P(n < X ≤ n+1) = 1/30 for every minute n=0,1,...29.

a)

P( X > 10) = 1 - P(X ≤ 10) = 1 - 10/30 = 2/3

b)

P(10 <  X ≤ 20) = (20-10)/30 = 1/3

7 0
3 years ago
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