Answer:
$7153.03
Step-by-step explanation:
To find the total amount after 3 years, we can use the formula for compound tax:
P = Po * (1+r/n)^(t*n)
where P is the final value, Po is the inicial value, r is the rate, t is the amount of time and n depends on how the tax is compounded (in this case, it is semi-annually, so n = 2)
For our problem, we have that Po = 5000, r = 12.3% = 0.123, t = 3 years and n = 2, then we can calculate P:
P = 5000 * (1 + 0.123/2)^(3*2)
P = 5000 * (1 + 0.0615)^6
P = $7153.029
Rounding to the nearest cent, we have P = $7153.03
Answer:
= - 282x
Step-by-step explanation:
- 6(14x - 23x + 56x)
= - 84x + 138x - 336x
= 54x - 336x
= - 282x
Answer:
$17,277.07
Step-by-step explanation:
Present value of annuity is the present worth of cash flow that is to be received in the future, if future value is known, rate of interest is r and time is n then PV of annuity is
PV of annuity = ![\frac{P[1-(1+r)^{-n}]}{r}](https://tex.z-dn.net/?f=%5Cfrac%7BP%5B1-%281%2Br%29%5E%7B-n%7D%5D%7D%7Br%7D)
= ![\frac{3000[1-(1+0.10)^{-9}]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-%281%2B0.10%29%5E%7B-9%7D%5D%7D%7B0.10%7D)
= ![\frac{3000[1-(1.10)^{-9}]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-%281.10%29%5E%7B-9%7D%5D%7D%7B0.10%7D)
= ![\frac{3000[1-0.4240976184]}{0.10}](https://tex.z-dn.net/?f=%5Cfrac%7B3000%5B1-0.4240976184%5D%7D%7B0.10%7D)
= 
= 
= 17,277.071448 ≈ $17,277.07
Answer:
In 10 seconds, the garden hose will emit 15 quarts of water.
Step-by-step explanation:
The amount of water emitted by the garden hose over time can be expressed as a ratio: 9/6, or 9 quarts of water for every 6 seconds of time. We can then simplify this ratio to 3/2, or 3 quarts of water for every 2 seconds of time. Since the ratio will remain constant, or the same, over time, we can set up an equivalent ratio, or fraction to find the amount of water emitted in 10 seconds: 3/2 = x/10. We look at the denominators and see that 2 x 5 = 10. In order to make the ratios equivalent, we would also multiply the numerator by 5: 3 x 5 = 15, which gives us the amount of water emitted in 10 seconds.
