The way to determine if a name is a variable holding a value or if it is a function call is by:
- Instance variables are prefixed with self.
<h3>What is this call about?</h3>
A function call is known to be a kind of an expression that has the function name which is said to be accompanied by the function call operator, () .
Note that The way to determine if a name is a variable holding a value or if it is a function call is by:
- Instance variables are prefixed with self.
See full question below
How do you determine if a variable in a method is an instance variable for the class?
a) Instance variables have leading underscores in their names.
b) Instance variables are prefixed with self..
c) Instance variables start with a capital letter.
d) all of the above
e) none of the above
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Answer:
O cannot be modified in this view.
O cannot have te added.
O can be inserted from a file or disk.
O will be permanent when added to the box
Answer:
C++.
Explanation:
#include <iostream>
using namespace std;
////////////////////////////////////////////////////////////////
void printPrime(int n) {
if (n > 0) {
cout<<2<<endl;
for (int i=3; i<=n; i++) {
bool isPrime = true;
for (int j=2; j<i; j++) {
if (i % j == 0) {
isPrime = false;
break;
}
}
if (isPrime == true)
cout<<i<<endl;
}
}
else {
cout<<"Invalid input";
}
}
int main() {
int n;
cout<<"Enter positive integer: ";
cin>>n;
printPrime(n);
return 0;
}
5
“var x = 5” declares a variable (var) called x and sets its value to 5.
I would say a because it was lots of letters and numbers