Answer:
Explanation:
try
clc
clear
close all
x=linspace(0,2*pi,7);
z=cos(pi.*x./3)
% the output on mine is to 4 decimals so it looks a bit different than what the output on your example is , but, I think if you change the format to decimal 2 it will look the same :)
Answer:
he just regrets that he made a monster and deeply feels guilty that it is in pain of reliving
Explanation:
Answer:
Theoretically Yes
Explanation:
The data given is linearly separable. So, the subset of the data will also be linearly separable. And it will pass for all training dataset. However, you should definitely never expect such thing In any real-life problem because the data is noisy, for a bazilion of reasons, so no model is guaranteed to perform perfectly.
The price could go up, it might not work then later down the road
