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4 years ago

The 5 in 6.052 has 1/10 the value of the 5 in? Is it 4.45, 53.2 , 7.5 or 0.815

1 answer:

4 0

The answer is: [D]: "0.815" .
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<span> The "5" in "6.052" has 1/10 the value of the "5" in: 0.815 .
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Virginia Beach is 10 miles wide and 30 miles long. If one inch of rain falls on Virginia Beach, how many cubic feet of rain fell

Arte-miy333 [17]

1 mile = 5280 feet.

Convert the dimensions to feet:

10 miles = 5280 x 10 = 52,800 feet

30 miles = 5280 x 30 = 158,400 feet

Multiply together to get the area:

52,800 x 158,400 = 8,363,520,000 square feet.

1 inch = 1/12 of a foot.

Multiply the area by 1/12 for the volume of rain:

8,363,520,000 x 1/12 = 696,960,000 cubic feet.

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3 years ago

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What number times it self 3 times equals 729

katrin2010 [14]

729 ÷ 3 = 243
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3 years ago

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

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3 years ago

What is the largest of three consecutive positive integers if the sum of the smaller two integers is 11

FromTheMoon [43]

Let, the numbers are: x, (x+1), (x+2)
Now, x+x+1 = 11
2x + 1 = 11
2x = 10
x = 5

So, largest number would be: (x+2) = (5+2) = 7

In short, Your Final answer would be 7

Hope this helps!

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4 years ago

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UNO [17]

Answer:

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Step-by-step explanation:

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