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Phoenix [80]
3 years ago
13

Simplify x/0.7 = 27 a. 17,9 b. -17.9 c. 18.9 d. -18.9

Mathematics
2 answers:
Zina [86]3 years ago
8 0
The answer is C. 18.9
To solve for x you cross multiply.
So x=.7(27)=18.9
Novosadov [1.4K]3 years ago
4 0

Im pretty sure the answer is C.18.9

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43 = 20 + z/3 please help
BabaBlast [244]

Answer:

z = 69

Step-by-step explanation:

43 - 20 = z/ 3

23 = \frac{z}{3}

cross multiply

z = 23 x 3

z =69

3 0
3 years ago
Will give brainliest!!
sladkih [1.3K]

Answer:

Infitite solutions (C)

Step-by-step explanation:

They are the same line.

6 0
3 years ago
A metalworker has a metal alloy that is 20​% copper and another alloy that is 60​% copper. How many kilograms of each alloy shou
puteri [66]
<h3>Answer:</h3>
  • <u>20</u> kg of 20%
  • <u>80</u> kg of 60%
<h3>Step-by-step explanation:</h3>

I like to use a little X diagram to work mixture problems like this. The constituent concentrations are on the left; the desired mix is in the middle, and the right legs of the X show the differences along the diagonal. These are the ratio numbers for the constituents. Reducing the ratio 32:8 gives 4:1, which totals 5 "ratio units". We need a total of 100 kg of alloy, so each "ratio unit" stands for 100 kg/5 = 20 kg of constituent.

That is, we need 80 kg of 60% alloy and 20 kg of 20% alloy for the product.

_____

<em>Using an equation</em>

If you want to write an equation for the amount of contributing alloy, it works best to let a variable represent the quantity of the highest-concentration contributor, the 60% alloy. Using x for the quantity of that (in kg), the amount of copper in the final alloy is ...

... 0.60x + 0.20(100 -x) = 0.52·100

... 0.40x = 32 . . . . . . . . . . .collect terms, subtract 20

... x = 32/0.40 = 80 . . . . . kg of 60% alloy

... (100 -80) = 20 . . . . . . . .kg of 20% alloy

6 0
3 years ago
Drinking and Driving Among High School Students The percentage of high school students who drink and drive stood at 17.5% at the
Vikki [24]

Answer:

Step-by-step explanation:

The percentage of high school students who drink and drive at the beginning of 2001   =   17.5%

The percentage of high school students who drink and drive at the beginning of 20011   =   10.3%

Rate of decrease = 17.5 - 10.3 / 10

= .72

The required linear function

f(t) =  - 0.72 x t + 17.5

b ) Rate of decrease in percentage = (17.5 - 10.3) / 10

= .72 %

c )  Percentage of high school students who drink and drive  at the beginning of 2014

t = 2014 - 2011 = 13

f(t) =  - 0.72 x t + 17.5

= - .72 x 13 + 17.5

= 8.14 %

6 0
3 years ago
Naomi works in a music shop and earns $42 per day. She earns an extra $2 for each CD she sells. If Naomi wants to earn at least
KengaRu [80]

Answer:

42 + 2n  ≥ 80

Step-by-step explanation:

Given,

Naomi's earnings for one day = $ 42,

Also, she earns extra $2 for each CD she sells,

Thus, the extra earning for n CDs = 2n dollars,

So, her total earning for a day if she sells n CDs = ( 42 + 2n ) dollars,

If Naomi wants to earn at least $80 per day,

Her total earning ≥ 80 dollars,

⇒ 42 + 2n  ≥ 80

Which is the required inequality.

8 0
3 years ago
Read 2 more answers
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