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Phoenix [80]
3 years ago
13

Simplify x/0.7 = 27 a. 17,9 b. -17.9 c. 18.9 d. -18.9

Mathematics
2 answers:
Zina [86]3 years ago
8 0
The answer is C. 18.9
To solve for x you cross multiply.
So x=.7(27)=18.9
Novosadov [1.4K]3 years ago
4 0

Im pretty sure the answer is C.18.9

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Solve this formula for the velocity for (d)<br><br> Show your work
Vinvika [58]

Answer:

d = vt

Step-by-step explanation:

Step 1: Write equation

v = d/t

Step 2: Multiply both sides by t

vt = d

Step 3: Rewrite

d = vt

7 0
2 years ago
Write a formula for the general term or nth term for the sequence. Then find the indicated term. five halves comma five fourths
nadya68 [22]
Sequence: 5/2, 5/4, 5/8, 5/16
a8=?

a1=5/2
a2=5/4
a3=5/8
a4=5/16

a2/a1=(5/4)/(5/2)=(5/4)*(2/5)=(5*2)/(4*5)=2/4=1/2
a3/a2=(5/8)/(5/4)=(5/8)*(4/5)=(5*4)/(8*5)=4/8=1/2
a4/a3=(5/16)/(5/8)=(5/16)*(8/5)=(5*8)/(16*5)=8/16=1/2
Ratio: r=a2/a1=a3/a2=a4/a3→r=1/2

an=a1*r^(n-1)
a1=5/2, r=1/2
an=(5/2)*(1/2)^(n-1)
an=(5/2)*[1^(n-1)/2^(n-1)]
an=(5/2)*[1/2^(n-1)]
an=(5*1)/[2*2^(n-1)]
an=5/2^(1+n-1)
an=5/2^n

n=8→a8=5/2^8
a8=5/256

Answers:
The formula for the general term or nth term for the sequence is an=5/2^n
a8=5/256
6 0
3 years ago
When pouring water from one five gallon bucket to another, a person tends to pour at a faster rate at first and then slow down i
Nitella [24]

I will assume that 0.62 is an exponent   then

amount left  after t seconds = f(6) =   5 - 0.82(6)^0.62

= 2.51 gallons to nearest hundredth.

4 0
3 years ago
Determine if the figures below are congruent? Explain why or why not. I need it for a test please answer fast!
Rus_ich [418]

Answer:

Yes they should be congruent ones just at a different angle.

Step-by-step explanation:

6 0
3 years ago
In a right triangle ABC, CD is an altitude, such that AD=BC. Find AC, if AB=3 cm, and CD= root 2 cm.
Nata [24]

Given CD is an altitude such that AD=BC , AB=3 cm and CD= √2 cm.

Let AD=x, Since given AB=3

                                     AD+DB=3

                                       x+DB = 3

                                        DB = 3-x

Since ΔBCD is rght angle triangle, let's apply Pythagoras theorem

BC^{2} = DB^{2} +CD^{2}

BC^{2} = (3-x)^{2} +(\sqrt{2} )^{2}

BC^{2} =(3-x)^{2} +2

Since given AD=BC,let us plugin BC=x in above step.

x^{2} =(3-x)^{2} +2

x^{2} =9-6x+x^{2} +2

6x=11

x=\frac{11}{6}

Now we know AD=x=\frac{11}{6} and given CD=√2.

Let us apply Pythagoras theorem for ΔACD

AC^{2} =AD^{2} +DC^{2}

AC^{2} = (\frac{11}{6} )^{2} +(\sqrt{2} )^{2}

AC^{2} =\frac{193}{36}

AC=\sqrt{\frac{193}{36} } = 2.315cm

3 0
3 years ago
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