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bearhunter [10]
3 years ago
11

What is 3 2/5 minus 1 4/5?

Mathematics
1 answer:
umka21 [38]3 years ago
4 0
You can convert that to 17/5 - 9/5 which equals 8/5
You might be interested in
Marla did 65 sit ups each day for 1 week. Use the distributive property to show an expression u can use to find the total number
Debora [2.8K]
<span>the total number of sit ups = 7(60 + 5)
                                          = 7 * 60 + 7 * 5
                                          = 420 + 35
                                          = 455

Hope it helps</span>
8 0
3 years ago
Help me please. The answer is 3350 but i need to do step by step. But i dont know how<br>​
Radda [10]

Answer:

3350

Step-by-step explanation:

100 + 8 = 108%

108% is 3618

100% is x

108x = 3618 * 100

108x = 361800

x = 361800/108

= 3350

Hence, the original salary is HRK 3350

<em>Feel free to mark this as brainliest! :D</em>

5 0
3 years ago
Simplify the equation. x/(x-4 )+ 4/(x-4 )
ANTONII [103]

Answer:

x+4/x-4

Step-by-step explanation:

=x/(x-4)+4/(x-4) [ l.c.m= (x-4)]

=x+4/x-4

6 0
3 years ago
??????????????????????
Leviafan [203]
√(x + 9) - 4 = 1
√(x + 9) - 4 (+4) = 1 (+4)
√(x + 9)(²) = 5(²)
x + 9(-9) = 25(-9)
x = 16

hope this helps

6 0
4 years ago
The mean June midday temperature in Desertville is 36°C and the standard deviation is 3°C.Assuming this data is normally distrib
AleksandrR [38]

Answer:

The value is  E(X) = 4 \ days

Step-by-step explanation:

From the question we are told that

   The mean is  \mu  =  36^oC

    The standard deviation \sigma =  3^oC

Generally the probability that in June , the midday  temperature is between  

39°C and 42°C is mathematically represented as

      P(39 <  X <  42) = P(\frac{39 - 36}{3}  < \frac{X - \mu }{\sigma} < (\frac{42 - 36}{3} )

\frac{X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ X )

      P(39 <  X <  42) = P(1  < Z

=>   P(39 <  X <  42) = P(Z   < 2) - P( Z

From the z table  the area under the normal curve to the left corresponding to  1 and  2  is

     P(Z   < 2)  = 0.97725

and

    P(Z   < 1)  = 0.84134

    P(39 <  X <  42) = 0.97725  - 0.84134

=>  P(39 <  X <  42) = 0.13591

Generally number of days in June would you expect the midday temperature to be between 39°C and 42°C

      E(X) =  n  *  P(39 <  X 42 )

Here n is the number of days in June which is  n = 30

       E(X) =  30  *   0.13591

=>    E(X) = 4 \ days

8 0
3 years ago
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