This seems disgusting to solve directly, so let's convert this to vertex form.
1) Divide all terms by 1/2:
2y = -x² - 4x + 14
2) Complete the square:
2y = -(x² + 4x - 14)
2y = -(x² + 4x + 4 - 4 - 14)
2y = -[(x + 2)² - 18]
2y = -(x + 2)² + 18
3) Rewrite in vertex form:
(x + 2)² = -2y + 18
(x + 2)² = -2(y - 9)
Now, we know the vertex is at (-2, 9)
It's a concave down parabola
The axis of symmetry is simply the x-ordinate of the vertex.
The focus is at (-2, 17/2)
The directrix is at (-2, 19/2)
The y-intercept is at y = 7
Answer:
Given:
- Total balls = 10
- Black balls = 3
- White balls = 7
⇒ P(black ball) = 3/10 = 0.3
⇒ P(white ball) = 7/10 = 0.7
If one ball is chosen at random and <u>replaced</u>, the probabilities do not change between the first and second ball.
Let event D = first ball is black
Let event S = second ball is black
P(D) = 0.3
P(S) = 0.3 (since the first ball is replaced)
⇒ P(D ∩ S) = P(D) × P(S)
= 0.3 × 0.3
= 0.09
For Independent Events we know that: P(A ∩ B) = P(A) × P(B)
Therefore, as P(D ∩ S) = P(D) × P(S) the events are independent.
16--(3) $17
17--(3) $64
18--(2) $18
Answer:
yes but like with 2 characters longer