Answer:
A = 20sinθ(6 + 5 cosθ) cm²
Step-by-step explanation:
Drop perpendiculars DE and CF to AB.
Then, we have congruent triangles ADE and BCF, plus the rectangle CDEF.
The formula for the area of the trapezium is
A = ½(a + b)h
DE = 10sinθ
AE = 10cosθ
BF = 10cosθ
EF = CD = 12 cm
AB = AE + EF + BF = 10cosθ + 12 + 10 cosθ = 12 + 20cosθ
A = ½(a + b)h
= ½(12 +12 + 20 cosθ) × 10 sinθ
=(24 + 20 cosθ) × 5 sinθ
= 4(6 + 5cosθ) × 5sinθ
= 20sinθ(6 + 5 cosθ) cm²
Answer:

Step-by-step explanation:
we know that
To find out the probability of hitting a ball into the circular hole, divide the area of the hole by the area of the playing area
Let
x ----> the area of the hole
y ----> the area of the playing game
so

we have

<em>Find the area of the hole</em>
The area of the circle (hole) is equal to

we have
----> the radius is half the diameter
assume

substitute


<em>Find the probability</em>

we have


substitute


Convert to percentage

Round to the nearest tenth

It is 296 that will the the right answer
2^3 * 2^-5 = 2^(3 + (-5) = 2^(3 - 5) = 2^-2