I did the first one but can you help me with the second one plz??

Mathematics

1 answer:

yanalaym [24]2 years ago

5 0

the only like-terms are on the right-hand-side, since the left-hand-side has only 1 term anyway.

$\bf \cfrac{5}{2}s=\cfrac{3}{2}s+s\implies \cfrac{5}{2}s=\cfrac{3}{2}s+\cfrac{s}{1}\implies \cfrac{5}{2}s=\stackrel{\textit{using the LCD of 2}}{\cfrac{(1)3s+(2)s}{2}} \\\\\\ \cfrac{5}{2}s=\cfrac{3s+2s}{2}\implies \cfrac{5}{2}s = \cfrac{5}{2}s$

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Need help due friday

Ronch [10]

Answer:

C. f(x) = 40(1/4)^x

Step-by-step explanation:

Check all the options:

When x = 0

A. f(x) = 1/4(40)^x

f(x) = 1/4(40)^0

f(x) = 1/4(1)

f(x) = 1/4

When x = 0

B. f(x) = 1/2(40)^x

= 1/2(40)^0

= 1/2(1)

f(x) = 1/2

When x = 0

C. f(x) = 40(1/4)^x

= 40(1/4)^0

= 40(1)

= 40

When x = 0

D. f(x) = 4(1/3)^x

= 4(1/3)^0

= 4(1)

= 4

7 0

2 years ago

Two missiles, A and B, are shot from two different launch pads. The path of missile A can be represented by the quadratic functi

Vilka [71]

It is required to find the highest altitude (in meters) .

For the given quadratic function ⇒⇒ A(t) = −(t − 11)² + 115
From the attached figure which represents the graph of the given function
the maximum will be at point (11,115)

So, the highest altitude (in meters) = 115 meter

and it will reach it at t = 11 seconds