Answer:
LXXXVII
Step-by-step explanation:
L=50 X=10 V=5 I=1
So basically you need to figure out what adds up to the 87. so use L, or 50. now XXX=30. so now you have 80 so we still have 7 left over, so we can write 7 I's or a 5, (V) and two I's. We should use the V and the I. So we take one V, or 5. and two I's which together is 7. which leads us too LXXXVII. also always remember to have the biggest number first, in this case the L (50).
Answer:
95/12 as an improper fraction.
Answer:
x=-6, y=1
Step-by-step explanation:
Let's solve your system by substitution.
y=x+7;−2x−11=y
Step: Solve y=x+7 for y:
y=x+7
Step: Substitute x+7 for y in −2x−11=y:
−2x−11=y
−2x−11=x+7
−2x−11+−x=x+7+−x(Add -x to both sides)
−3x−11=7
−3x−11+11=7+11(Add 11 to both sides)
−3x=18
−3x/
−3
=
18/
−3 (Divide both sides by -3)
x=−6
Step: Substitute−6 for x in y=x+7:
y=x+7
y=−6+7
y=1 (Simplify both sides of the equation)
Answer:
x=−6 and y=1
Answer:
5 chickens
Step-by-step explanation:
Let's set chickens and pigs with variables "c" and "p" respectively.
We know there a 16 animals in all, so there are:
c+p=16
We know there are 54 legs and chickens have 2 legs and pigs have 4 legs each:
2c+4p=54
Now we have our system of equations:
c+p=16
2c+4p=54
We are trying to find the number of chickens, so we write the first equation in respect to c.
p=16-c
Substituting the first derived equation to equation two:
2c+64-4c=54
Simplifying:
64-2c=54
2c=10
c=5
So there are 5 chickens.
