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3 years ago

Please help DO NOT IGNORE DO NOT IGNORE

Mathematics

1 answer:

lisov135 [29]3 years ago

3 0

Answer:

24.997 cm

Step-by-step explanation:

Find the diameter:

7(2) = 14 cm

Find the circumference:

C = $\pi d$

C = $\pi (14)$

C = 43.988

Divide the circumference by 4:

43.988/4 = 10.997

(This is the length of the curved side)

Add length to the other 2 sides:

7 + 7 + 10.997 = 24.997

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4. The students in Mr. Michael’s art class are decorating a booth for Harvest Day. They have blue cloth that is 60 inches long,

MrRissso [65]

Length of blue cloth is 60 inches , length of gold cloth is 48 inches and length of white cloth is 72 inches.

a.

As, the length of all pieces are equal, so for getting the greatest possible length of the pieces, we need to find GCF(greatest common factor) of 60, 48 and 72.

First we will factor out all three numbers completely......

$60=2*2*3*5\\ \\ 48=2*2*2*2*3\\ \\ 72=2*2*2*3*3$

The common factors are: 2, 2 and 3

Thus the GCF $= 2*2*3=12$

So, the greatest possible length of the pieces without having any cloth left over will be 12 inches.

b.

For finding the number of pieces for each color cloth, we will just divide the length of each cloth by 12. So...

Number of pieces for blue cloth $=\frac{60}{12}=5$

Number of pieces for gold cloth $=\frac{48}{12}=4$ and

Number of pieces for white cloth $=\frac{72}{12}=6$

4 0

3 years ago

Someone please help me

Kitty [74]

Answer:

0.45, 4, 2, 1.5

Step-by-step explanation:

14/3 = 4.66667

Numbers less than 14/3 are 0.45, 4, 2, 1.5.

8 0

2 years ago

The fish population in a certain lake rises and falls according to the formula F = 3000(23 + 11t − t2). Here F is the number of

Gemiola [76]

Answer:

a) On January 1, 2017 the fish population will be the same as the initial population.

b) On September 18th, 2018 the fish population will be zero.

Step-by-step explanation:

Hi there!

a) First, let´s write the function:

F(t) = 3000(23 + 11t − t²)

The population on January 1, 2006 is the population at t = 0. Then:

F(0) = 3000(23 + 11· 0 - 0²)

F(0) = 3000 · 23 = 69000

This will be the population every time at which t² - 11t = 0. Then let´s find the other value of t (besides t = 0) that makes that expression to be zero:

t² - 11t = 0

t(t - 11) = 0

t = 0

and

t - 11 = 0

t = 11

On January 1, 2017 (2006 + 11), the fish population will be the same as the initial population.

b) We have to obtain the value of t at which F(t) = 0

F(t) = 3000(23 + 11t − t²)

0 = 3000(23 + 11t − t²)

divide both sides of the equation by 3000

0 = 23 + 11t − t²

Let´s solve this quadratic equation using the quadratic formula:

a = -1

b = 11

c = 23

x = [-b ± √(b² - 4ac)] / 2a

x = 12.8 ( the other value of x is negative and therefore discarded).

After 12.8 years all the fish in the lake will have died.

If 1 year is 12 months, 0.8 years will be:

0.8 years · 12 months/year = 9.6 months

If 1 month is 30 days, 0.6 month will be:

0.6 month · 30 days / month = 18 days

All the fish will have died after 12 years, 9 months and 18 days from January 1, 2006. That is, on September 18th, 2018.

7 0

3 years ago

can somone help me on my last question its a math one so if your good at math can you please help me on that one

svp [43]

Answer:

show me the question you need

Step-by-step explanation:

4 0

2 years ago

Write the equation of the line that passes through the points (- 4, - 3) and (3, - 5) . Put your answer in fully reduced slope i

bekas [8.4K]

Answer:

(-4, -3) y (3, -5)

{-12 y, 15 y}

-12 y + 15 y = 3 y

(3 y)/2

3 sqrt(41) abs(y)

6 0

2 years ago