Answer:
324 and 144
Step-by-step explanation:
We require
a₁, a₂, a₃, a₄
where a₂ and a₃ are the required geometric means
The n th term of a geometric sequence is
= a₁
where a₁ is the first term and r the common ratio
Here a₁ = 729 and a₄ = 64, thus
729(r³) = 64 ( divide both sides by 729 )
r³ = 
( take the cube root of both sides )
r = ![\sqrt[3]{\frac{64}{729} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7B729%7D%20%7D)
= 
, then
a₂ = 729 × = 81 × 4 = 324
a₃ = 324 × = 36 × 4 = 144
Thus
729, 324, 144, 64
Compose the quadratic condition in standard shape, ax2 + bx + c = 0. Recognize the values of a, b, c. Write the Quadratic Equation. At that point substitute within the values of a, b, c. Simplify. Check the arrangements.
Answer:
The answer is C: (2x +3, 2y)
Step-by-step explanation:
When applying the dilation of a scale factor of 2, you have to apply it to both the x and y coordinate, which means you are multiplying the coordinates by 2.
Let's assume the coordinates you start with are (x, y). Apply the dilation of 2.
(x, y) -----> (2x, 2y)
Now you are moving the figure right. When moving right, this only effects the x coordinate since the x axis moves left and right. Moving right indicates you will add the number of units translated to the x coordinate.
Translation 2 units right:
(2x, 2y) -----> (2x +3, 2y)
Answer:
A={3,4,5,...,}
Step-by-step explanation:
Roster form means that we list each element of the set within curly braces
(6,4)
in another answers : x = 6 , y = 4
(6,4)
