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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Gwar [14]3 years ago

7 0

Me rn but no one will answer my question

Dmitry [639]3 years ago

4 0

Okay jsnsjsjsjjsjshshshshshhshshsus

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Find the coefficient of the squared term in the simplified form for the second derivative, f "(x) for f(x) = (x3 + 2x + 3)(3x3 −

diamong [38]

$Use:\\(h(x)\cdot g(x))'=h'(x)g(x)+h(x)g'(x)\\\\h(x)=x^3+2x+3\to h'(x)=3x^2+2\\\\g(x)=3x^3-6x^2-8x+1\to g'(x)=9x^2-12x-8\\\\f(x)=(x^3+2x+3)(3x^3-6x^2-8x+1)\\\\f'(x)=(x^3+2x+3)'(3x^3-6x^2-8x+1)+(x^3+2x+3)(3x^3-6x^2-8x+1)'\\\\=(3x^2+2)(3x^3-6x^2-8x+1)+(x^3+2x+3)(9x^2-12x-8)\\\\=9x^5-18x^4-24x^3+3x^2+6x^3-12x^2-16x+2+9x^5-12x^4-8x^3+18x^3-24x^2-16x+27x^2-36x-24\\\\=18x^5-30x^4-8x^3-6x^2-68x-22$

$f''(x)=(18x^5-30x^4-8x^3-6x^2-68x-22)'\\\\=90x^4-120x^3-24x^2-12x-68\\\\Answer:\ \boxed{-24}$

7 0

3 years ago

Read 2 more answers

Help quick please help hep

____ [38]

Answer:

Step-by-step explanation:

There are 4 people that are 27 and 4 people that are 29. Both are <em>older</em> than 26.

4 0

3 years ago

X(3 + 4 + 8) + 7 hhelp pls

11111nata11111 [884]

Answer:

15x + 7

Step-by-step explanation:

To solve the equation, you distribute the x to all the terms within the parentheses. When you distribute, you get:

3x + 4x + 8x + 7

Add all the like terms and you get the final answer.

8 0

3 years ago

A sample of 80 high school seniors,45% were are female were surveyed as to wheather or not they are employed outside of school ,

Nataliya [291]

The first thing we must do for this case is find the number of boys surveyed.
We have then:
(1-0.45) * (80) = 44
We are now looking for the number of boys employed.
We have then:
(1-0.25) * (44) = 33
Answer:
there are 33 boys employed.

4 0

4 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

4 0

3 years ago