Ok so assuming you ahve a rectangle (since you gave legnth and width)
area=legnth times width
perimiter=L+L+W+W=2L+2W=2(L+W)
area=36
some factors are
6 and 6
4 and 9
3 and 12
2 and 18
1 and 36
those are only whole numbers, but tat is for ease
so add and mutliplyby 2 (preimiter
6 and 6, P=2(6+6)=24
4 and 9, P=2(4+9)=26
3 and 12, P=2(3+12)=30
2 and 18, P=2(2+18)=40
1 and 36, P=2(1+36=74
Answer:
D.
Step-by-step explanation:
Set this up as a ratio with #parts of tank on top and #minutes on the bottom and then solve it as a proportion with x being the unknown number of minutes in the second ratio.

Notice the 1 in the numerator of the second ratio. This is because a whole tank is represented by 9/9 which is the same thing as 1.
Cross multiply to solve for x:

To solve for x we will multiply both sides by 9/5:

9/5 and 5/9 cancel each other out when multiplied leaving simply "x" on the left. And multiplying on the right:

which divides to 3.6 minutes
From least to greatest
1) cup
2) pint
3) quart
4) liter
5) gallon
The ratio shown in fraction form would be;

Now to convert it to its simplest form, you need to find their greatest common factor; (so in this case it would be 28...cause 28 goes into 56 evenly)
*Now divide both terms by
28
28 ÷ 28 =
1
56 ÷ 28 =
2
so your ratio 28 to 56 in simplest form is..

Hope this helps :)
Answer:
<u>The measure of the arc CD = 64°</u>
Step-by-step explanation:
It is required to find the measure of the arc CD in degrees.
So, as shown at the graph
BE and AD are are diameters of circle P
And ∠APE is a right angle ⇒ ∠APE = 90°
So, BE⊥AD
And so, ∠BPE = 90° ⇒(1)
But it is given: ∠BPE = (33k-9)° ⇒(2)
From (1) and (2)
∴ 33k - 9 = 90
∴ 33k = 90 + 9 = 99
∴ k = 99/33 = 3
The measure of the arc CD = ∠CPD = 20k + 4
By substitution with k
<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>