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Anni [7]
2 years ago
15

How are the two functions f(x) = 0.7(6)x and g(x) = 0.7(6)–x related to each other?

Mathematics
2 answers:
marissa [1.9K]2 years ago
9 0

Answer:

b

Step-by-step explanation:

edge 2021 -2020

slavikrds [6]2 years ago
6 0

Answer:

It's B

Step-by-step explanation:

edge2021

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Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−2).
kap26 [50]

Let g(x) = 2x and h(x) = x2 + 4. Evaluate (h ∘ g)(−2).

A. −12

the corrects answer is <em>B. −16 </em>

C. 20

D. 16

7 0
3 years ago
Read 2 more answers
Find the missing side length.
Dmitry [639]

Answer:

4 cm, if you subtract 9 from 13 you get four.

8 0
3 years ago
45% of what number is 27?
gtnhenbr [62]
45% of what number is 27

0.45x = 27
x = 27 / 0.45
x = 60 <== 45% of 60 = 27
5 0
3 years ago
Find the number of roots for each equation.<br> 5. 5x4 + 12x3 – x2 + 3x + 5 = 0
pav-90 [236]

Answer:

The number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

Step-by-step explanation:

Here, the given function polynomial is :

P(x) : 5x^4 + 12x^3 – x^2 + 3x + 5 = 0

The Fundamental Theorem of Algebra says that a polynomial of degree n will have exactly n roots (counting multiplicity).

Now here, the degree if the polynomial is 4 (highest power of variable x).

So, according to the Fundamental Theorem, the given polynomial can have AT MOST 4 roots, counting Multiplicity.

Hence,  the number of roots for  equation 5x^4 + 12x^3 – x^2 + 3x + 5 = 0 is 4 .

7 0
3 years ago
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