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3 years ago

Factor the expression 6x^2 + 5x + 1

Mathematics

2 answers:

Ivahew [28]3 years ago

8 0

Answer:

(2x + 1)(3x + 1)

Step-by-step explanation:

Given

6x² + 5x + 1

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 6 × 1 = 6 and sum = + 5

The factors are + 3 and + 2

Use these factors to split the x0 term

6x² + 3x + 2x + 1 ( factor the first/second and third/fourth terms )

= 3x(2x + 1) + 1 (2x + 1) ← factor out (2x + 1) from each term

= (2x + 1)(3x + 1) ← in factored form

Brilliant_brown [7]3 years ago

4 0

Answer:

The factors are (3x+1)(2x+1)

Step-by-step explanation:

The expression is:

6x^2 + 5x + 1

We have to break the middle term to find its factors. For this first we have to multiply the coefficient of 1st terms with the constant term:

6*1 = 6

Now we have to find any two numbers whose product is 6 and whose sum is the middle term:

3*2=6

3+2=5

Now break the middle term by these two numbers.

6x^2 + 5x + 1

6x^2+3x+2x+1

Group the first two terms and last two terms:

(6x^2+3x)+(2x+1)

Now take out common factor from each term:

3x(2x+1)+1(2x+1)

(3x+1)(2x+1)

Therefore the factors are (3x+1)(2x+1)....

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3 years ago

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mars1129 [50]

Answer:

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Step-by-step explanation:

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3 years ago

Assume that when adults with smartphones are randomly selected, 42% use them in meetings or classes. If 5 adult smartphone use

Dmitrij [34]

Answer:

The probability that exactly 2 of 5 use their smartphones in meetings or classes is 0.3442.

Step-by-step explanation:

Let X = number of adults who use smartphones in meetings or classes.

The probability of the random variable X is, P(X) = p = 0.42

A sample of n = 5 adult smartphone users are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

Compute the value of P (X = 2) as follows:

$P(X=2)={5\choose 2}0.42^{2}(1-0.42)^{5-2}\\=10\times 0.1764\times0.195112\\=0.344177\\\approx0.3442$

Thus, the probability that exactly 2 of 5 use their smartphones in meetings or classes is 0.3442.

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4 years ago

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velikii [3]

Answer:

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3 years ago