Solution: (-Infinite, -8/3] U (4, Infinite)
Using that a fraction is greater than or equal to zero when the numerator and denominator have the same sign:
a/b>=0. Then we have two cases:
Case 1) If the numerator is positive, the denominator must be positive too (at the same time):
if a>=0 ∩ b>0
Or (U)
Case 2) If the numerator is negative, the denominator must be negative too (at the same time):
if a<=0 ∩ b<0
In this case a=3x+8 and b=x-4, then:
Case 1):
if 3x+8>=0 ∩ x-4>0
Solving for x:
3x+8-8>=0-8 ∩ x-4+4>0+4
3x>=-8 ∩ x>4
3x/3>=-8/3 ∩ x>4
x>=-8/3 ∩ x>4
Solution Case 1: x>4 = (4, Infinite)
Case 2):
if 3x+8<=0 ∩ x-4<0
Solving for x:
3x+8-8<=0-8 ∩ x-4+4<0+4
3x<=-8 ∩ x<4
3x/3<=-8/3 ∩ x<4
x<=-8/3 ∩ x<4
Solution Case 2: x<=-8/3 = (-Infinite, -8/3]
Solution= Solution Case 1 U Solution Case 2
Solution = (4, Infinite) U (-Infinite, -8/3]
Solution: (-Infinite, -8/3] U (4, Infinite)
20.000+4.000+0.357+0.05+0.007
14-2x=6+12x
14=6+10x
8=10x
0.8=x
Answer:
x^3+9x^2+27x+27
Step-by-step explanation:
The answer is true because, you must use the distribute then add both sides by 24 then divide both sides by -3 and then you will come up with your answer x=-1 which means that statement is true
