Now in 2012 there was an increase 8%, so you will add 8 to your previous answer 108 and receive 116. So now there was 16 more passengers in 2012 than in 2010. Transfer the 16 passengers into 16% and you now have your answer.

3 0

2 years ago

Andrew is about to leave for school. If he walks at a speed of 50 meters per minute, he will arrive 3 minutes after the bell rin

Mariana [72]

Answer:

The answer is: 13 minutes

Step-by-step explanation:

First Let us form equations with the statements in the two scenario

$time=\frac{distance}{speed}$

Let the time in which the bell rings be 'x'

1. If Andrew walks (50 meters/minute), he arrives 3 minutes after the bell rings. Therefore the time of arrival at this speed = (3 + x) minutes

$3 + x =\frac{distance}{50}\\distance = 50(3+x) - - - - - (1)$

2. If Andrew runs (80 meters/minute), he arrives 3 minutes before the bell rings. Therefore the time taken to travel the distance = (x - 3) minutes

$x - 3 = \frac{distance}{80} \\distance = 80(x-3) - - - - - (2)$

In both cases, the same distance is travelled, therefore, equation (1) = equation (2)

$50(3+x)=80(x-3)$

$150 +50x=80x-240\\$

Next, collecting like terms:

$150 + 240 = 80x - 50x\\390 = 30x\\30x = 390\\$

dividing both sides by 3:

x = 390÷30 = 13

∴ x = 13 minutes

7 0

3 years ago

Help someone please help me on tis

Angelina_Jolie [31]

Answer:

I think its b)1.5 seconds sorry if I am wrong

Step-by-step explanation:

16t²=time

16t²=16²seconds

16² seconds=256 seconds

16t²+64=distance

256+64=320

320 feet=distance

256 seconds/320feet

=1.5seconds

5 0

3 years ago