Answer:
P = 0.4812
Step-by-step explanation:
First, we need to use here two expressions and then do the calculations.
The first one is the conditional probability which is:
P(B|A) = P(A∩B)/P(A) (1)
The second expression to use has relation with the Bayes's theorem which is the following:
P(D|C) = P(C|D)*P(D) / P(C|D)*P(D) + P(C|d)*P(d) (2)
Now, the expression (2) is the one that we will use to calculate the probability of a selected random bicyclist who tests positive for steroids.
So, in this case, we will call C for positive and D that is using steroids and d is the opposite of d, which means do not use steroids.
Then, the probabilities are the following:
P(D) = 8% or 0.08
P(C|D) = 96% or 0.96
P(C|d) = 9% or 0.09
P(d) = 1 - 0.08 = 0.92
With these data, let's replace in expression 2
P(D|C) = 0.96 * 0.08 /0.96 * 0.08 + 0.09*0.92
P(D|C) = 0.0768 / 0.1596
P(D|C) = 0.4812 or 48.12%
Answer:
5x^2 + 20x
Step-by-step explanation:
5x(x+4)
5x*x + 5x*4
5x^2 + 20x
From the expression <span>8(x +4) (y +4) (z 2 + 4z + 7),
</span>the factors are 8, (x+4), (y+4), <span>(z^2 + 4z + 7) since each of these factors, when you divide that to the whole expression won't give a remainder</span>
Answer:
The domain is discrete
Step-by-step explanation:
Given
Required
What type of domain is it?
<em>Based on the given options, the domain is continuous.</em>
From the question, we understand that x represents the hours spent in climbing the rock.
The climber can decide to climb for 1 hour, 2 hours, ½ hour, ⅓ hour, ¼ hour, etc..
A domain is said to be discrete if it can only take integers (i.e. whole numbers), if otherwise, it is continuous;
So, since x is not limited to only whole numbers, then we can conclude that the domain of x is continuous
Answer:option B is the correct answer
Step-by-step explanation:
The formula for poisson distribution is expressed as
P(x = r) = (e^- µ × µ^r)/r!
Where
µ represents the mean of the theoretical distribution.
r represents the number of successes of the event.
From the information given,
µ = 2.19
For the probability of no accidents on this section of highway during one day period, r = 0
Therefore,
P(x = 0) = (e^- 2.19 × 2.19^0)/0!
P(x = 0) = (e^- 2.19 × 1)/1
P(x = 0) = 0.112
