Answer:
By AA
ΔWXY ~ΔWVZ
Step-by-step explanation:
Here WXY is an isosceles triangle with legs WX & WY
So WX = WY
Hence ∠X = ∠Y
So ∠2= ∠3.
Now by angle sum property
∠1 + ∠2+∠3 = 180°
∠1+∠2+∠2=180°
2∠2 = 180° - ∠1 .......(1)
In triangle WVZ
WV = WZ
So ∠V = ∠Z
∠4 = ∠5
Once again by angle sum property
∠1 + ∠4 + ∠5=180°
∠1 + ∠4 + ∠4 = 180°
2∠4 = 180° - ∠1 ...(2)
From (1) & (2)
2∠2 = 2∠4
∠2=∠4
Now ∠W is common to both triangles
Hence by AA
ΔWXY ~ΔWVZ
To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothegm. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothegm = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.
Answer:
The bird has to fly 7.5 m
Step-by-step explanation:
Please see diagram in attached image.
Notice that there is a right angle triangle that defines the situation, and you know two elements of such triangle;
1) one acute angle (), and
2) the side opposite to that angle.
What you need to find is the side adjacent to the angle, which is what the bird needs to fly horizontally to be above the fish. We named that "x".
The trig function that relates such triangle elements is the tangent:
which rounded to the nearest tenth is: 7.5 m
We have to determine the equation of the line passing through the point (2,-5) and parallel to the line
When two lines are parallel, then the slopes of the two lines are equal.
Equation of line with point and slope 'm' is given by:
Since, we have to determine the equation of a line with point (2,-5).
So, the equation of the line is :
Since, the line is parallel to the line
So,
So, slope of the line 'm' is .
Therefore, the equation of the line is:
Therefore, is the required equation of the line.