Answer:
Step-by-step explanation:
The question is faulty. It works once it gets to + 1, +2, +3
The other x values should be 0 and - 1 instead of -1 and -3.
Here's the formula I get.
f(x) = 2*3^(2x + 1)
f(0) = 2*3^(1)
f(0)= 6
f(-1) = 2*3^(-2 + 1)
f(-1) = 2*3^(-1)
f(-1) = 2/3
f(-2) = 2*3^(-2*2 + 1)
f(-2) = 2*3^(-4 +1)
f(-2) = 2*3^(-3)
f(-2) = 2/27
Since my answers do not agree with the given answers, I can do nothing more to help you. I will pass this along to someone I know who will see through it.
Answer:
well coins are smaller value i guess and dollars you have bigger numbers
Answer:
[See Below]
Step-by-step explanation:
Here are some pictures to help you.
The 'template' for a quadratic function is:

, where <em>a</em> is the vertical stretch/compression factor.
If the <em>a</em> in f(x) is 2/5, then vertically stretching the function is done by multiplying the function by 2, making:
Answer:
Radical Form is 1/√9
Step-by-step explanation:
Also, the decimal version is 0.3 repeating