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Arturiano [62]
3 years ago
6

Tracey pays $8.50 of her monthly life insurance premium, and her employer covers the rest. If her monthly premium is $32.25, wha

t is the annual value to Tracey of this benefit
Mathematics
1 answer:
strojnjashka [21]3 years ago
8 0
If i calculated it right it should be 23.75
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x=−8,y=7

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Assume that y varies inversely with x. If y=1/3 when x=1/2, find y when x=1/4.
LenKa [72]

Answer:

y = \frac{2}{3}

Step-by-step explanation:

Given that y varies inversely with x then the equation relating them is

y = \frac{k}{x} ← k is the constant of variation

To find k use the condition y = \frac{1}{3} when x = \frac{1}{2} , thus

\frac{1}{3} = \frac{k}{\frac{1}{2} } = 2k ( divide both sides by 2 )

k = \frac{1}{6}

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When x = \frac{1}{4} , then

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3 years ago
Which hiker walks farther in one hour which is faster
levacccp [35]

They hiked the same distance because they were hiking at the same rate.

5 0
2 years ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

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3 years ago
On a road map the distance between two cities is 2.5 in the map scale is 1 inch equals 30 miles what is the actual distance betw
Elenna [48]

Answer:

98

Step-by-step explanation:

duh

8 0
3 years ago
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