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Feliz [49]
3 years ago
7

What angles do you see in the letters E F L

Mathematics
2 answers:
lana [24]3 years ago
4 0
Right angles - 90 degrees
alex41 [277]3 years ago
3 0
All those letters have right angles in them :)
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The answer is 0..................
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Please help asap 30 pts
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  last choice d

Step-by-step explanation:

4| x - 3| - 8 = 8

| x-3| - 2 = 2

| x-3| = 4      we have two cases:

(a) x - 3 = 4     for x >= 3

x=7

(b) -1( x-3 ) =4  for x < 3

x = -1



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Multiplying fractions. Eight ninths times four fifths
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6 0
3 years ago
For what values of θ, −π ≤ θ ≤ π, is y = tan θ undefined?
pogonyaev

Answer:

The answer is II and IV ⇒ the 3rd answer

Step-by-step explanation:

* lets check the domain of angle Ф

∵ -π ≤ Ф ≤ π

∵ y = tanФ

∵ tanФ = sinФ/cosФ

* The effective term which makes tanФ undefined is cosФ

- If cosФ = 0, than tanФ will be undefined

* Lets check the angles that have cosФ = 0

∵ The unit circle intersect x-axis at point (1 , 0) and (-1 , 0)

∵ The unit circle intersect y-axis at point (0 , 1) and (0 , -1)

∵ cosФ = x-coordinates of the points

∵ The points of intersection with the y-axis have x- coordinates = 0

∴ The angles on the y-axis have cosФ = 0

* The angles on the +ve part of y-axis are π/2 and -3π/2

 The angles on the -ve part of y-axis are -π/2 and 3π/2

∴ The tan of π/2 , 3π/2 , -π/2 , -3π/2 undefined

* In the problem

I. -π ⇒ defined ⇒ on the -ve part of x-axis

II. -π/2 ⇒undefined

III. 0 ⇒ defined ⇒ on the +ve part of the x-axis

IV. π/2 ⇒ undefined

V. π ⇒ defined ⇒ on the -ve part of x-axis

∴ The answer is II and IV ⇒ the 3rd answer

3 0
3 years ago
PLEASE CAN ANYONE HELP!!!
DiKsa [7]

Answer:

x = 3

y = 4  

hey, I am not 100% sure of the certainty of my answers, I am using what I remember about that topic but I do not know if it is right or wrong, I hope I have helped you, I did what I could.

Step-by-step explanation:

-3x + 2y = 23

5x + 2y = -17

X solution:

(you cancel the y)

-3x = 23

5x = -17

(you combine all the values above with those below)

2x = 6

(solve the ecuation normaly)

x = 6/2 = 3

Y solution:

(you replace the x)

-3(3) + 2y = 23

5(3) + 2y = -17

-9 + 2y = 23

15 + 2y = -17

(you combine all the values above with those below)

6 + 4y = 6

(solve the ecuation normaly)

4y = 0

y = 4  

(I do not really know if the answer here is 0 or 4 since when passing the 4 to divide it would be 0/4 and I do not understand very well how that is solved)

6 0
3 years ago
Read 2 more answers
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