So with this, you can rewrite the equation as: $(3x^2\times x^2)+(3x^2\times -3x)+(3x^2\times 2)+(-4x\times x^2)+(-4x\times -3x)+(-4x\times 2)+(5\times x^2)+(5\times -3x)+(5\times 2)$

Firstly, solve the multiplication: $3x^4+(-9x^3)+6x^2+(-4x^3)+12x^2+(-8x)+5x^2+(-15x)+10$

Next, combine like terms, and <u>your answer will be: $3x^4-13x^3+23x^2-23x+10$ </u>

7 0

2 years ago

Alona [7]

You’re absolutely amazing and I really appreciate that you’re trying to help others! And if you need anything yourself please feel free to ask :)

5 0

2 years ago

Who do I do this problem

Leviafan [203]

You subtract 16 from each side of the equation.
Then it will say exactly what number 'n' is.
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The equation is n + 16 = 9

On the left side, you subtract 16 from (n + 16) and you have 'n'.

On the right side, you subtract 16 from 9 and you have -7 .

Now the equation says n = -7

3 0

2 years ago