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jek_recluse [69]
4 years ago
7

In a basic sine curve, where can the zeros NOT be found?

Mathematics
2 answers:
Lemur [1.5K]4 years ago
4 0

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we know that

f(x)=\sin x

It is an odd function.

It has a period of 2π because the sine wave repeats after every 2π units.

It value lies between -1 and 1.

And we know that

\sin 0^\circ=0^\circ

And 0 occurs exactly middle of -1 and 1.

So, the zeroes can be found in the middle, beginning and at the end.

But at maximum point, there will be no zero.

As when it attains its maximum point, it won't touch x-axis.

Hence, Option 'C' is correct.

Papessa [141]4 years ago
3 0
The most brainliest answer A) middle
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VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

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The vertices are:

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Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

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2 years ago
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          4        4
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