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AVprozaik [17]
3 years ago
12

There are 28 nonfiction books and 35 fiction books in the teacher's collection. Which of the following expresses the ratio of no

nfiction books to fiction books in simplest form?A.
B.
C.
D.

13 points
Mathematics
2 answers:
Lostsunrise [7]3 years ago
5 0
The answer is B) 4:5

First write the ratio out. To find the simplified expression, divide by the greatest common factor (GCF). In this case, the GCF of 28 and 35 is 7.

28:35
--- ----
7    7
=4:5

4:5 is the simplest form because you cannot simplify it further.
iogann1982 [59]3 years ago
4 0
The ratio of nonfiction books to fiction its gonna be : 28/35 and the simplest one is 
28 ÷ 7 /35 ÷7 = 4/5 and thats the simplest one :)))
i hope this be helpful
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Find the roots of h(t) = (139kt)^2 − 69t + 80
Sonbull [250]

Answer:

The positive value of k will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80, roots are those values of t so that h(t) = 0. That is:

19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0 (1)

Roots are determined analytically by the Quadratic Formula:

t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}

t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }

The smaller root is t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }, and the larger root is t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321}  }.

h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80 has one real root when \frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0. Then, we solve the discriminant for k:

\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}

k \approx \pm 0.028

The positive value of k will result in exactly one real root is approximately 0.028.

7 0
2 years ago
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Mademuasel [1]
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2 years ago
<img src="https://tex.z-dn.net/?f=obtain%20the%20fourier%20expansion%20for%20sin%20ax%20in%20the%20interval%20-%20%7C%20%20%20%5
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andrew-mc [135]

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Step-by-step explanation:

The formula for the area of a triangle is height times base (or width) divided by 2. It is written as:

BxH/2

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Artyom0805 [142]

A=h/2(a+b) solver for h

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