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Brut [27]
3 years ago
9

Len needs to run at least 3 miles a day to get ready for a cross-country race. One lap of the school track is 400 yards. If len

runs
10 laps a day will he cover at least 3 miles? Explain
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0
No because 4 laps around the track is one mile so if he did then he would have only done two and a half miles
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Pls help due ASAP <br> Show workings pls
kobusy [5.1K]
The answer is c
you (4,4) and another point need to be double (2,-5) so the other point needs to add to (4,-10) so 4 + 0 is 4 and 4 + - 14 = 10
4 0
3 years ago
Can anybody help me with this bellwork?
aev [14]
First, find the amount of time is taken to travel 1 mile :
time taken to travel 1 mile = 20/6 = 3 ⅓ mins
hence, time taken to travel 9 miles = 3 ⅓ x 9 = 30 mins

time taken to travel 10 miles = 3 ⅓ x 10 = 33 ⅓ mins
6 0
3 years ago
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A friend of mine is giving a dinner party. His current wine supply includes 9 bottles of zinfandel, 10 of merlot, and 12 of cabe
e-lub [12.9K]

Answer:

Step-by-step explanation:

From the given information:

The total number of wine = 9 + 10 + 12 = 31

(1)

The number of distinct sequences used for serving any five wines can be estimated by using the permutation of the number of total wines with the number of wines served.

i.e

= ^{31}P_5

=\dfrac{31!}{(31-5)!}

=\dfrac{31!}{(26)!}

=\dfrac{31\times 30\times 29\times 28\times 27\times 26!}{(26)!}

= 20389320

(2)

If the first two wines served = zinfandel and the last three is either merlot or cabernet;

Then, the no of ways we can achieve this is:

= ^9P_2\times ^{22}P_3

= \dfrac{9!}{(9-2)!}\times \dfrac{22!}{(22-3)!}

= \dfrac{9!}{(7)!}\times \dfrac{22!}{(19)!}

= \dfrac{9*8*7!}{(7)!}\times \dfrac{22*21*20*19!}{(19)!}

= 665280

(3)

The probability that no zinfandel is served is computed as follows:

Total wines (with zinfandel exclusion) = 31 - 9 = 22

Now;

the required probability is:

= \dfrac{^{22}P_5 }{^{31}P_5}

= \dfrac{\dfrac{22!}{(22-5)!} } {\dfrac{31!}{(31-5)!} }

= \dfrac{\dfrac{22!}{17!} } {\dfrac{31!}{(26)! }}

= \dfrac{(\dfrac{22*21*20*19*18*17!}{17!})} {(\dfrac{31*30*29*28*27*26!}{(26)! })}

= 0.1549

≅ 0.155

4 0
3 years ago
Find the vaule of x really need help plz
LenaWriter [7]

Answer:

14

Step-by-step explanation:

3 0
3 years ago
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HELPPP ASAP WILL MARK BRAINLEST!!!
Blababa [14]

Answer:

B

Step-by-step explanation:

Eagles  | Frequency

0-4                 4

5-9                 5

10-14             3

15-19             2

4 0
3 years ago
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