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VashaNatasha [74]
2 years ago
15

Solve the the equation tan(x+pi/3) = sqrt 3/3 over the interval [0, 2].

Mathematics
1 answer:
kupik [55]2 years ago
7 0

Rewrite the right side as √3/3 = 1/√3, and recall that tan(x) = 1/√3 when x = π/6. Then since tan is π-periodic, taking the inverse tan of both sides gives

\tan\left(x + \dfrac\pi3\right) = \dfrac1{\sqrt3} \implies \tan^{-1}\left(\tan\left(x + \dfrac\pi3\right)\right) = \tan^{-1}\left(\dfrac1{\sqrt3}\right) + n\pi

\implies x + \dfrac\pi3 = \dfrac\pi6 + n\pi

where n is any integer. Solving for x, we get

x = -\dfrac\pi6 + n\pi

and the solutions in the interval [0, 2π] are x = 5π/6 and x = 11π/6 (for n = 1 and n = 2).

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3 0
3 years ago
Read 2 more answers
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3 years ago
Which expression is equivalent to b + b - 0.56b?
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Hey there!

“Which expression is equivalent to b + b – 0.56b?”

• “b” or any other letter value is considered an “unknown number” so usually we label it/them as an invisible 1

• COMBINE the LIKE TERMS

(b + b – 0.56b)

(1b + 1b – 0.56b)
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• Therefore, b + b – 0.56b is equivalent to 2b + 0.56b

Possible answer that you could be looking for: 2b + 0.56b ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)
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