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3 years ago

What is the absolute value of 9.8 and of 10/3?

Mathematics

1 answer:

devlian [24]3 years ago

6 0

9.8 divided by 10\3
multiply both sides by 3 to get rid of the 3
(9.8 x3=29.4)then divide by 10 to get 2.94

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DIstributive property to match equivalent expression 7(-4-x)

Ugo [173]

Answer:

-28-7x

Step-by-step explanation:

You mulitply 7 by -4 to get -28 and then mulitply 7 by -x to get -7x

3 0

3 years ago

Can you guys help me solve this equation with step-by-step help, please...

Alex

Step-by-step explanation:

-2x - 5y = 16___(1)

2x - 3y = -16___(2)

(1) + (2) ==> -2x -5y = 16

(+) 2x -3y = -16

-8y = 0

y = 0/-8

y = 0

y=0 in (1)

(1)---> -2x-5y =16

-2x - 5(0) = 16

-2x - 0 = 16

-2x = 16

x = 16/-2

x = -8

x = -8 , y = 0

-5x + 2y = 11__(1) ; -3x + 4y = -13___(2)

multiply eqn(1) with 2

2 × (1) : -10x + 4y = 22___(3)

(3) - (2) :. -10x + 4y = 22

(-) -3x + 4y = -13

-7x = 35

x = 35/-7

x = -5

x=-5 in (1)

(1) : -5x + 2y = 11

-5(-5) + 2y = 11

25 + 2y = 11

2y = 11 - 25

2y = -14

y = -14/2

y = -7

x = -5 , y = -7

4 0

2 years ago

Value of the digit 3 in 20,320

Tema [17]

I believe that the answer is 300

8 0

3 years ago

Read 2 more answers

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x

= $64 + 192 \times x^{1} + 240 \times x^{2}$ + terms involving higher powers of x

so, the first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

Again,

$(2+x - x^{2})^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})$

Now, by inspection,

the term $x^{2}$ comes from k =5 and k = 6

for k = 5, the coefficient of $x^{2}$ is , $(-32) \times 6$ = -192

for k = 6 , the coefficient of $x^{2}$ is, $6_{C_{2}} \times 2^{4}$ = 240

so, coefficient of $x^{2}$ in the final expression = (240 - 192) = 48

3 0

3 years ago

5x-4=-3-x so ya can yall help

Ket [755]

Step-by-step explanation:

5x-4=-3-x

5x+x=4+(-3)

6x=1

x=1/6

4 0

3 years ago

Read 2 more answers