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3 years ago

4 1/4 = 16/blank + 1/4

Mathematics

1 answer:

Tomtit [17]3 years ago

5 0

Answer:

The “blank” is 4

Step-by-step explanation:

4 1/4= 16/x+ 1/4

We want to get rid of the 1/4. So we subtract it from both sides and get

4= 16/x

We know that if we put 16 divided by 4, you get 4.

This gives you 4= 16/4.

This is your final answer.

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Use the table to determine what percent of students prefer school uniforms and what percent do not prefer school uniforms. What

Ahat [919]

16 + 4 = 20

16/20 = 80% or 4/5 (20 x 5 = 100, 16 x 5 = 80)

4/20 = 20% or 1/5 (20 x 5 = 100, 4 x 5 = 20)

The relationship is that more students do not prefer school uniforms compared to the ones that do prefer them.

Hope this helps!

3 0

3 years ago

Determine whether the function f(x)=x^3+x^2 is even odd or neither

TiliK225 [7]

Answer: neither

Explanation:

x^3 can be either even or odd
Ex: x = 2 then 2^3 = 8 = even
Ex: x = 3 then 3^3 = 27 = odd

x^2 can also be either even or odd
Ex: x = 2 then 2^2 = 4 = even
Ex: x = 3 then 3^3 = 9 = odd

Since both can be even and odd

Even/Odd + Even/Odd = Even/Odd

So the result will be either even or odd

5 0

3 years ago

Denise collects stuffed animals. The number of stuffed animals in her collection, a, after n, number of years, can be described

natka813 [3]

I think the answer would be A

5 0

3 years ago

Find a in a=6b if b=2

Rina8888 [55]

Answer:

a=12

Step-by-step explanation:

if a=6b

and b=2

a=2×6

a=12

4 0

3 years ago

Read 2 more answers

P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }

balandron [24]

The solution to the division of the given surd is: $\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

<h3>Division of Surds.</h3>

The division of surds follows a systemic approach whereby we divide the whole numbers separately and the root(s) are being divided by each other.

Given that:

$\mathbf{P=(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} ) : \frac{4x}{(x-1)^{2} }}$

i.e.

$\mathbf{=\dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )}{ \frac{4x}{(x-1)^{2} }} }$

Using the fraction rule:

$\mathbf{\dfrac{a}{\dfrac{b}{c}}= \dfrac{a\times c}{b}}$

$\mathbf{\implies \dfrac{(\frac{\sqrt{x} +2}{x-1}+\frac{\sqrt{x}\\ -2}{x-2\sqrt{x} +1} )(x-1)^{2}}{4x}} }$

By simplification, we have:

$\mathbf{ =\dfrac{\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{2} }{4x} }$

$\mathbf{P =\dfrac{(6\sqrt{x}-x^2\sqrt{x}-3x\sqrt{x}+2x+2)(x-1) }{8x} }$

Learn more about evaluating the division of surds here:

https://brainly.in/question/27942899

#SPJ1

6 0

2 years ago