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3 years ago

Find a in a=6b if b=2

Mathematics

2 answers:

Marat540 [252]3 years ago

7 0

A = 12
since b = 2, the equation would become
a = 6(2)

Rina8888 [55]3 years ago

4 0

Answer:

a=12

Step-by-step explanation:

if a=6b

and b=2

a=2×6

a=12

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When a ray bisects an angle, it does all of the following except what?

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Shares a side with the angle.

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3 years ago

F(x)=∣x∣

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Answer:

Step-by-step explanation:

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3 years ago

Evaluate. 4 (−3) (−2) Can I have Some Help....

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Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

What is the volume of the prism?

Nikitich [7]

Answer:

24 m³

Step-by-step explanation:

We need to find the volume of the prism. Given that , rectangular prism with cubic units arranged in two rows of two with six total layers . And the volume of each unit is 1 m³ .

Volume of one unit :-

$\rm\implies Volume_{one\ unit } = 1m^3$

By Unitary Method :-

Volume of two cubes , will be :-

$\rm\implies Volume_{two\ unit } = 2m^3$

Volume of one layer :-

$\rm\implies Volume_{one\ layer } = 4m^3$

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3 years ago

Given the following information about a hypothesis test of the difference between two means based on independent random samples,

HACTEHA [7]

Answer:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

Step-by-step explanation:

Data given:

$n_1 =13$ represent the sample size for group 1

$n_2 =10$ represent the sample size for group 2

$\bar X_1 =12$ represent the sample mean for the group 1

$\bar X_2 =9$ represent the sample mean for the group 2

$s_1=5$ represent the sample standard deviation for group 1

$s_2=3$ represent the sample standard deviation for group 2

We are assuming two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The pooled variance is given by:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

4 0

4 years ago

Find a in a=6b if b=2​

Find a in a=6b if b=2