f(x)=3x^2-18x+10
a = 3, b = -18 and c = 10
The vertex of a parabola is in form a(x+d)^2 + e
d = b/2a = -18/2(3) = -18/6 = -3
e = c-b^2/4a = 10 - -18^2/4(3) = 10-27 = -17
Now the vertex form of the parabola becomes 3(x-3)^2 -17
Use the vertex form of the parabola in the vertex form of y = a(x-h)^2 +k
Where a = 3, h = -3 and k = -17
Now you have y = 3(x-(-3))^2 +(-17)
Simplify: y = 3(x+3)^2 -17
The vertex becomes the h and k values of (3,-17)
It is a because it can’t be B and it can’t be C and it can’t be D so my answer is a
When you divide exponents you subtract the bottom one from the top one. The correct answer would be the first choice.
The expression should simplify to: X^4
Mass of the cat=5000g =5kg
Hence the tiger is 135/5=27 heavier than the mass of the cat
