Answer:
<h2>-7.1z +7.81</h2>Step by step explanation:
Multiply each term in paranthesis by -7.1
Multiply:
Hope this helps...
Good luck on your assignment..
A sample space for the experiment is {A, B, C, D, E, F, G}. Let W represent the event “the card is white”, let S represent “the
card is shaded”, and let L represent “the number is less than 3”. Select all that apply.
A. The event W is {A, C, G}.
B. The event W or L is {A, D, F, G}.
C. The event W and L is {A, G}.
D. The event not L is {B, C, E, F}.
E. P(W or S) = 1
F. P(W and S) = 0
A. The event W is {A, C, G}.
B. The event W or L is {A, D, F, G}.
C. The event W and L is {A, G}.
D. The event not L is {B, C, E, F}.
E. P(W or S) = 1
F. P(W and S) = 0
1 answer:
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Answer:
(a)
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b)
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by
Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4
Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Answer:
The answer to your question is letter D
Step-by-step explanation:
Rational equation
Simplify
Cancel the denominators and expand
3x² + 1 + x² - x = 4x - 4 + 4
Simplify
4x² - x + 1 - 4x = 0
4x² - 5x + 1 = 0
Factor
4x² - 4x - 1x + 1 = 0
4x(x - 1) - 1(x - 1) = 0
(4x - 1)(x - 1) = 0
x₁ = 1/4 x₂ = 1