2) Write the equation of the line that passes through the point (-3, -1) with a slope of -2/3.
2 answers:
Y=mx+b
slope=m
yint=b
we are given
slope=-2/3
point=(-3,-1)
y=-2/3x+b
input point -3,-
x=-3
y=-1
find b
-1=-2/3(-3)+b
-1=2+b
minus 3
-3=b
y=-2/3x-3
answer is D
The right answer is B i am just hoping that it is the right
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