Could you give the question more clear?
Answer: A = ≈28.55 cm²
Step-by-step explanation:
It is drawn as if it should be a triangle minus a rectangle with an area of
½(10)(13) - (7)(6) = 23 cm²
However it is not to scale.
The angle on the right side is
θ = arctan10/13 = 37.56859...°
Meaning the right triangle has a height of
h = 4tan37.56859 = 3.07692 cm
So the right triangle has an area of
Ar = ½(3.07692)(4) = 6.15384... cm²
The left hand side consists of a triangle over a rectangle
The height of the triangle is 4, the base is is 4/tan37.56859 = 5.2 cm
so the left area is
(2)(6) + ½(5.2)(4) = 22.4 cm²
So the sum of the areas of the two enclosed shapes is
A = 22.4 + 6.15384... = 28.55384... ≈28.55 cm²
Answer:
(b) a = 50 * 2^(t/4)
(c) 951
Step-by-step explanation:
After t hours
a = 50 * 2^(t/4)
After 17 hours
a = 50 * 2^(17/4)
a = 50 * 2^(4.25)
Use calculator
a = 951.3656920022
Rounded
a = 951
To form an equation with the given information, we use the formula :
y = mx + b, m being the slope and b being the y-intercept.
Since it is given that the slope is -9/7, we substitute m with -9/7.
y = -9/7x + b
To find b, we will substitute the known coordinates into the equation :
At point (-7 , 4), x = -7, y = 4
4 = -9/7 (-7) + b
4 = 9 + b
b = 4 - 9
b = -5
Now we know that b = -5, we will substitute b = -5 into the equation that we found earlier, y = -9/7 x + b :
y = - 9/7x - 5
To make it more readable, we can multiply the equation by 7:
7y = -9x - 5
7y + 9x + 5 = 0
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Answer : 7y + 9x + 5 = 0
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M must equal 20 to make the function to be linear
