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olchik [2.2K]
3 years ago
14

What's (-1,4), y=3x+5?

Mathematics
1 answer:
forsale [732]3 years ago
3 0

Answer:

(-1,4)

-1 is x and 4 is y

You have to plug it in for the equation:

4= 3(-1)+5

4= -3+5

4 = 2

the answer is no solution because 4 does not equal to 2

You might be interested in
one number is 4 more than another number. if 4 times the smaller number is decreased by twice the larger number. the result is 1
soldier1979 [14.2K]

x and x+4 are the numbers

3x=2(x+4)

3x=2x+8

3x-2x=8

x=8

x+4=12


3 0
3 years ago
Determine whether the statement is true or false. If f and g are positive increasing functions on an interval I, then fg is incr
Leno4ka [110]

Answer: false

Step-by-step explanation:

If f and g are increasing on I, this implies that f' > 0 on I and g' > 0 on I. That is both f' and g' have a positive slope. However,

Using product rule;

(fg)' = fd(g) + gd(f)

(fg)' = f * g' + f' * g

and although it is given that g' and f' are both positive we don't have any information about the sign of the values of the functions themselves(f and g). Therefore, if at least one of the functions has negative values there is the possibility that the derivative of the product will be negative. For example;

f = x, g = 5x on I = (-5, -2)

f' = 1 and g' =5 both greater than 0

f and g are both lines with positive slopes therefore they are increasing, but f * g = 5x^2 is decreasing on I.

6 0
3 years ago
Can someone answer this question please WBA’s wee it correctly if it’s correct I will mark you brainliest
oksano4ka [1.4K]

Answer:

\frac{1}{6}*\frac{4}{13}

Step-by-step explanation:

A 6 sided die has 6 outcomes.

Your sister picks from a 13 - slice plate meaning the fact that there are 13 outcomes.

There are 4 yellow slices so picking a yellow slice has a \frac{4}{13} chance

You need to mutiply both displayed values to solve this problem.

\frac{1}{6}*\frac{4}{13}

6 0
3 years ago
You have in the class 11 boys and 8 girls. You also have 3 seniors, 4 juniors, and 12 sophomores. If you select a student at ran
Daniel [21]

Answer:

38

Step-by-step explanation:

5 0
3 years ago
It is desired to compare the hourly rate of an entry-level job in two fast-food chains. Eight locations for each chain are rando
notka56 [123]

Answer:

It can be concluded that at 5% significance level that there is no difference in the amount paid by chain A and chain B for the job under consideration

Step by Step Solution:

The given data are;

Chain A 4.25, 4.75, 3.80, 4.50, 3.90, 5.00, 4.00, 3.80

Chain B 4.60, 4.65, 3.85, 4.00, 4.80, 4.00, 4.50, 3.65

Using the functions of Microsoft Excel, we get;

The mean hourly rate for fast-food Chain A, \overline x_1 = 4.25

The standard deviation hourly rate for fast-food Chain A, s₁ = 0.457478

The mean hourly rate for fast-food Chain B, \overline x_2 = 4.25625

The standard deviation hourly rate for fast-food Chain B, s₂ = 0.429649

The significance level, α = 5%

The null hypothesis, H₀:  \overline x_1 = \overline x_2

The alternative hypothesis, Hₐ:  \overline x_1 ≠ \overline x_2

The pooled variance, S_p^2, is given as follows;

S_p^2 = \dfrac{s_1^2 \cdot (n_1 - 1) + s_2^2\cdot (n_2-1)}{(n_1 - 1)+ (n_2 -1)}

Therefore, we have;

S_p^2 = \dfrac{0.457478^2 \cdot (8 - 1) + 0.429649^2\cdot (8-1)}{(8 - 1)+ (8 -1)} \approx 0.19682

The test statistic is given as follows;

t=\dfrac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{S_{p}^{2} \cdot \left(\dfrac{1 }{n_{1}}+\dfrac{1}{n_{2}}\right)}}

Therefore, we have;

t=\dfrac{(4.25-4.25625)}{\sqrt{0.19682 \times \left(\dfrac{1 }{8}+\dfrac{1}{8}\right)}} \approx -0.028176

The degrees of freedom, df = n₁ + n₂ - 2 = 8 + 8 - 2 = 14

At 5% significance level, the critical t = 2.145

Therefore, given that the absolute value of the test statistic is less than the critical 't', we fail to reject the null hypothesis and it can be concluded that at 5% significance level that chain A pays the same as chain B for the job under consideration

3 0
2 years ago
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