Let $A = (5,12)$, $B = (0,0)$, and $C = (14,0)$. For a point $P$ in the plane, the minimum value of $PA^2 + PB^2 + PC^2$ can be
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Answer:
6.25 km
Step-by-step explanation:
Here is the correct question: A park is 4 times as long as it is wide. If the distance around the park is 12.5 kilometers, what is the area of the park?
Given: Perimeter (Distance) of the park= 12.5 km
Considering park is in rectangular shape.
Let the width of park be x
∴ as given length will be 4x.
Formula for perimeter of rectangle =
Perimeter is given 12.5 km
⇒
⇒
∴ x= 1.25 km, which means width is 1.25 km and length is 5 km.
Now, finding the area of park
Formula; Area of rectangle=
∴ Area of rectangle=
∴Area of park will be 6.25 km.