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Keith_Richards [23]
3 years ago
15

Find the values of a and b so that the solution of the linear system is (-9,1).

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
6 0

Answer:

Step-by-step explanation:

we can write -9 instead of x and y=1 instead of 1

so we write solution again

-9a+1b=-31

-9a-1b=-41

-18a=-72

a=4

we should write 4 instead of a

-9(4)+1b=-31

-36+b=-31

b=5

a=4

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Polynomial function in standard form with zeros 5,-4,1
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Answer:

\boxed{\sf \ \ \  x^3-2x^2-19x+20 \ \ \  }

Step-by-step explanation:

hello,

by definition we can write

(x-5)(x+4)(x-1)

as 5,-4,1 are the zeroes

now we have to write it in the standard form, let's do it

(x-5)(x+4)(x-1)=(x^2+4x-5x-20)(x-1)\\=(x^2-x-20)(x-1)=x^3-x^2-20x-x^2+x+20\\=x^3-2x^2-19x+20

hope this helps

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Answer:

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 Rewriting we have:
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