Answer:
3:1:12
Step-by-step explanation:
Step-by-step explanation:
Hey there!
The equation of a line which passes through the point (1,1) is <em>(y-1) = m1 (x-1)...............(i)</em> {using one point formula}
Also, another equation which is perpendicular to the line is <em>y = 1/5 x + 4/5..........(ii)</em>
Comparing equation (ii) with y= mx+c, we get;
Slope (m2) = 1/5.
Now, As per the condition of perpendicular lines,
m1*m2 = -1
or, m1 * 1/2 = -1
or, m1= -2
Therefore, m1 = -2.
Keeping the value of m1 in equation (i) we get;
y-1 = -2(x-1)
y-1 = -2x+1
or, y+2x-2= 0
Therefore, the required equation is 2x+y-2= 0.
Hope it helps!
Answer:
D
Step-by-step explanation:
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Answer:
Product of two expression is 
Step-by-step explanation:
Given : Expression - 
and 
To find : The product of given expression
Solution : To find the product we apply distributive law
We write in the form of product and multiply term by term
Apply distributive law,
Therefore, Product of two expression is
