The graph on #6 describes a scatterplot. Because years of experience is the input, this makes the starting salary our output. Finding the best fitting line in a scatterplot requires the line to follow a trajectory similar to that of the points. As a result, there will be outliers. Since I don't know what "the calculator" is meant by this problem, I have used a different program. I hope it works for you. Good luck.
Answer:
Step-by-step explanation:
AB/AC =1/2
(3x-4)/(2x+12)=1/2
2(3x-4) = 1(2x+12)
6x-8=2x+12
4x=20
X=5
AC/BC =3x-4/7x-2=22/33=2/3
AB/AC=3x-4/7x-2=22/33=2/3
AB/AC=3x-4/2x+12
6x-8=2x+12
You would get 4/5 still trying to work out the last mark
Answer:
2 6/30 and 1 25/30
Step-by-step explanation:
First, you need to find 30÷5 and 30÷6. You do this because you need to know the multiplier when you create an equivalent fraction. 30÷5 is 6 and 30÷6 is 5. 2 1/5. You need to multiply the 1 and 5 by 6, that is 2 6/30. 1 5/6. 5 and 6 multiplied by 5 is 25 and 30. 1 5/6=1 25/30
-5x(x+3)-7(x-3)/x^2-9= -5x^2-15x-7x+21/x^2-9= -5x^2-22x+21/x62-9
