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givi [52]
3 years ago
14

If the strength of the magnetic field at B is 6 units, the strength of the magnetic field at A is ? 1.5 , 0.75 units , 24 units

, 10.6 units
Mathematics
2 answers:
Vadim26 [7]3 years ago
8 0

Answer:

1. The strength of magnetic field at A is 64 unit, then the magnetic field strength at B. is 256 units.

64 × 64 = 256 units.

2. If the strength of magnetic field B is 6 units then the strength magnetic field at A is 24 units.

which is 256 : 4 = 16 units.

Magnetic field is one of the two ways where the intensity of magnetic field is being expressed.

shepuryov [24]3 years ago
4 0

Answer:

A is 24

Step-by-step explanation:

if b is 6 I think you multiply 4 and get your answer of 24

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The ratio of the side length of a square to the square's perimeter is always 1 to 4.
makvit [3.9K]

Answer:

Side length of square (inches): 1 ,2, 4, 7

Perimeter of square (inches). : 4, 8, 16, 28

Step-by-step explanation:

Ratio is 1:4 (S:P).

So:

#:8, #=2. This is because 2/8 and 1/4 both = 0.25.

#:16, #=4. 4/16=0.25

7:#, #=28. 4x7=28, 7/28=0.25

Hope that helps

7 0
2 years ago
Factor the expression 10x+12 using the GCF <br><br> 10x+12=
lana [24]

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6 0
3 years ago
A homeowner's backyard is a rectangle with width 18 yards long and length 16 yards long. They plan to put in a square pool with
Ugo [173]

Answer:

Step-by-step explanation:

Given the dimension of the  homeowner's backyard to be width 18 yards long and length 16 yards long, the area of the rectangular backyard id expreesed as;

Area of rectangle = Length * Width

Area of the rectangular backyard = 18yards * 16yards

Area of the rectangular backyard = 288yards²

If they plan to put in a square pool with side length 5 yards long in the backyard, the area of the pool = 5yd*5yd = 25yd²

The remaining area that will contain the tiles = Area of the rectangular backyard -  area of the pool

The remaining area that will contain the tiles = 288yd² - 25yd² = 263yd²

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4 0
3 years ago
Using the x,y format where does the graph of 3x+3 and -5×+7 intersect
IRINA_888 [86]
Not sure if I'm right but I believe they intersect at (1,4).
8 0
3 years ago
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netineya [11]

Answer:

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Step-by-step explanation:

m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(-1,\,-1)\ \implies\ x_1=-1\,,\ y_1=-1\\(0,\,4)\ \implies\ x_2=0\,,\ y_2=4\\\\m=\dfrac{4-(-1)}{0-(-1)}=\dfrac{5}{1}=5

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x_1=-1\,,\ y_1=-1\,,\ m=5\\\\equation:\\{}\qquad\qquad y-(-1)=5\big(x-(-1)\big)\\\\{}\qquad\qquad y+1=5\big(x+1\big)

6 0
3 years ago
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