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4 years ago

Given Quadrilateral ABCD≅Quadrilateral EFGH , which statement is true?

Mathematics

2 answers:

Lynna [10]4 years ago

7 0

A should be correct. hope this helped

Genrish500 [490]4 years ago

7 0

Answer:

option B

Step-by-step explanation:

We are given that a quadrilateral ABCD is congruent to quadrilateral EFGH

We have to find the correct statements about the given quadrilaterals

When two quadrilaterals are congruent then every side of one quadrilateral is congruent to its corresponding side of another quadrilateral.

By definition of congruent quadrilaterals we have

Side EF is congruent to side AB

BC is congruent to FG

CD is congruent to GH

AD is congruent to EH

Therefore, option B is true.

Answer : option B

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What is the slope of this non-vertical line?

ikadub [295]

There is no slope to a non vertical line

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3 years ago

Draw the image of the following segment after a dilation centered at the origin with a scale factor of 2/3

Irina18 [472]

Answer:

Step-by-step explanation:

Let the ends of the given segment are A and B.

Coordinates of A → (8, 6)

Coordinates of B → (12, 12)

If a point (x, y) is dilated by a scale factor 'k' about the origin, rule to be followed,

(x, y) → (kx, ky)

If k = $\frac{2}{3}$

(x, y) → $(\frac{2}{3}x, \frac{2}{3}y)$

By this rule coordinates of the image points of A and B will be,

A(8, 6) → $A'(\frac{2\times 8}{3},\frac{2\times 6}{3})$

→ A'(5.3, 4)

B(12, 12) → $B'(\frac{12\times 2}{3}, \frac{12\times 2}{3})$

→ B'(8, 8)

Now we can get the image of segment AB after dilation by a scale factor of $\frac{2}{3}$ .

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3 years ago

A is plotted on a coordinate grid at start bracket 3 and 1 over 2, negative 1 end bracket.. Choose the correct grid that best sh

dalvyx [7]

Answer:

A coordinate grid that shows a point located halfway between 3 and 4 units to the right and 1 unit down from the origin

Step-by-step explanation:

In a coordinate grid, the y axis is plotted on the vertical axis and the x axis is plotted on the horizontal axis. A is plotted on a coordinate grid at ( $3\frac{1}{2},-1$ ) i.e ( $\frac{7}{2},-1$ ). Above the origin is the positive y axis, below the origin is the negative y axis, right of the origin is the positive x axis and left of the origin is the negative x axis.

To plot A on the coordinate axis we need to locate $3\frac{1}{2}$ on the x axis and -1 on the y axis. $3\frac{1}{2}$ is halfway between 3 and 4, since the x coordinate is positive it is located to the right between 3 and 4 and since the y coordinate is negative it is located 1 unit down from the origin.